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9x^2+50x-20000=0
a = 9; b = 50; c = -20000;
Δ = b2-4ac
Δ = 502-4·9·(-20000)
Δ = 722500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{722500}=850$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-850}{2*9}=\frac{-900}{18} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+850}{2*9}=\frac{800}{18} =44+4/9 $
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